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- Finding out the name of the OLE file associated with a control
- Modifying the content of an OLE control
- Displaying the content of an OLE binary memo
- Miscellaneous
Initializes an OLE control with an OLE object. The OLE server is invoked to load the OLE object. The OLE object appears in the field: the field is updated. The server is not started. Note: Depending on the server that created the OLE object, the object may be displayed in the field as: - its bitmap representation. Example: image created with Paint Brush.
- its vector representation. Example: worksheet created with Excel.
- the icon representing the server. Example: WinWord icon.
- text.
// Load the object
OLELoad(OLE_OLE2, "OBJECT1.OLE")
// Process the object
// Save the object
OLESave(OLE_OLE2, "OBJECT1.OLE")
Sintaxis
<Result> = OLELoad(<OLE control> , <File name>)
<Result>: Boolean - True if the OLE object was loaded,
- False otherwise.
<OLE control>: Control name Name of OLE control to initialize. If this parameter corresponds to an empty string (""), the control to which the current event belongs will be used. <File name>: Character string Name of OLE object. This object must have been created by OLESave. Observaciones Finding out the name of the OLE file associated with a control To find out the name of the OLE file associated with a control, use the following syntax: FileName = OLE_OLE1 // OLE_OLE1 is the name of the control
Modifying the content of an OLE control To modify the name of the file associated with a control, use the following syntax: OLE_OLE1 = FileName // OLE_OLE1 is the name of the control
This line of code is equivalent to OLELoad(OLE_OLE1, FileName). Displaying the content of an OLE binary memo To display the content of an OLE binary memo, use the following syntax: OLELoad(ControlName, DataFileName.ItemName) For example: OLELoad(OLE_OLE1, Product.OLEMemo)
Only OLE version 1 is supported.
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